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Picking Numbers works well on many Number Properties
questions, but sometimes it's necessary to know Number Property rules
in order to solve a problem. At other times, familiarity with the rules
will help get you to the correct answer more efficiently. For the following
Roman Numeral question, we will focus on the Number Property rules that
are being tested. Review the question and then proceed to the task below.
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This question stem suggests that
two Number Properties concepts will be central to solving this problem.
What are they? |
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1:
2:
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We have identified the two Number Properties
concepts with which we're dealing. Now we must figure out how they
apply to the question at hand. Our first rule involves odd/even number
combinations. Which of the following odd/even combinations results
in an odd number? Select all combinations that apply and then click
Continue. |
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The only odd/even combination that results in
an odd sum is our last option, 1 odd and 1 even number. Conceptually,
this makes sense - even numbers are multiples of 2, and therefore consist
of pairs of numbers with no 'leftovers'. The sum of two even numbers will
also consist of pairs of numbers with no 'leftovers'. An example will
illustrate: 8 (4 pairs) + 2 (1 pair) = 10 (5 pairs).
Two odd numbers also result in even numbers when
summed. This is because an odd number consists of pairs of numbers (essentially
an even number) plus another number. The two additional numbers combine
to create another pair: 3 (1 pair, plus 1) + 5 (2 pairs, plus 1) = 8 (4
pairs).
Applied to our question stem, this rule indicates
that x must be odd and y must be even, or vice versa.
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