- Two points on line L are (0, -1) and (3, -3). What is the slope-intercept form of the equation of L?
Answer:
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope of the line, and b is the y-intercept. Since we are given two points, we can calculate the slope m as follows:
Note that the slope is the same if we interchange the order of the points.
We know that the y-intercept, b = -1 since the line crosses the y-axis at the point (0, -1). Also, remember that the y-intercept, b, is the value of ywhen x = 0.
Therefore, the equation of the line with m = -2/3 and b = -1 is given by:
y = (-2/3)x – 1
- A line has equation:
iy - 2 = (-1/2)(x + 3)
What is the equation of this line in slope-intercept form?
Answer:
The given equation is in slope-point form, that is:
y - y1 = m(x - x1)
where m is the slope of the line and (x1, y1) is a point on the line. We can use algebraic operations to convert it to slope-intercept form.
The last equation above is in slope-intercept form. The slope is m = -1/2, and the y-intercept is b = 1/2.
Examples: Real-World Applications of Slope-Intercept Form
- In physics, an object moving in a straight line with constant acceleration will have a final velocity, v, given by the equation:
v = at + u
where a is the constant acceleration, u is the initial velocity and t is the elapsed time. This equation is known as a kinematic equation. Notice that this equation is in slope-intercept form, y = mx + b. In the comparison of the two equations below, corresponding variables and constants are shown with the same color.
In the kinematic equation, t is your x variable, v is your y variable, a is the slope and u is the y-intercept.
Suppose an object has an initial velocity of 18 m/s (meters per second) and is accelerating at -3 m/s^2 (meters per second squared). The negative acceleration value simply means that the object is slowing down or decelerating. What is the velocity of the object after 4 s (seconds)?
Answer:
Here we can use the kinematic equation, v = at + u with a = -3 and u = 18. At elapsed time t = 4 s:
v = (-3)(4) + 18 = 6 m/s
Note that the object has slowed down from 18 m/s to 6 m/s in 4 seconds.
- With $10 in my pocket, I decided to take a taxi from the Chicago Union Train Station to my workplace, a total distance of 3.75 miles. The taxi charges a flat amount of $2.25 plus $0.45 per quarter mile traveled. What is the equation (in slope-intercept form) that relates the number of quarter miles traveled and total cost of the taxi ride? Did I have enough money for the ride?
Answer:
We need an equation that relates the number of quarter miles traveled and the total cost of the taxi ride. Let x = number of quarter miles traveled, and y = total cost of taxi ride. We can write our equation in slope-intercept form as:
y = 0.45x + 2.25
where the slope, m = 0.45, and the y-intercept, b = 2.25. The total distance between the train station and my workplace is 3.75 miles or 15 quarter miles (Note: there are fifteen ¼ miles in 3.75 miles). Therefore, the total cost for the taxi ride is:
y = 0.45(15) + 2.25 = $9.
Yes, I had enough money for the ride.
Below is the graph for the equation y = 0.45x + 2.25. The point (15, 9) is plotted on the graph, which shows that I could have gone a little over 17 quarter miles with my $10!