Using the Quadratic Formula
Now, we can substitute these values into the quadratic formula and evaluate the resulting expression to find our answers! While this is theoretically pretty straightforward, there are quite a few spots that can easily trip you up. Because this is our first time, let's evaluate this one step by step together and go over some of the common mistakes. We're going to have to remember our order of operations and make sure we also keep track of all our negative signs.
For this problem, then, the first thing we'll have to take care of is the exponent we see. The exponent I see is a 2, which means a square, which means multiply that number by itself, so we do 4 * 4 to get 16. Next in the order of operations will come multiplication. Doing the multiplication on the inside of the square root (4 * -1 * 7) gives us -28, then doing the multiplication on the bottom of the fraction (2 * -1) is simply -2. We're now left with x = (-4 +/- sq. root 16 - -28) / -2, and we're going to focus on the inside of the square root in the top of the fraction.
The inside of the square root in the formula is b^2 - 4ac. This part is one of the hardest parts to evaluate and one of the easiest parts to make a mistake on. It also has a special name; it's called the discriminant. It has some important features that we'll talk about in other lessons, but for this lesson, you just need to know to be careful when evaluating it, specifically for the reason I'm about to mention. Notice that we ended up with a -28 after we did the multiplication, but I still have 16 - -28. Minus a negative is plus a positive, so 16 + 28 gives us 44.
The most mathematically correct answer for example #1
ow that we have the square root of 44, we'd like to check to see if we can take the square root of 44 nicely. Is there a number that, multiplied by itself, gives us 44? Well, 7 * 7 is 49, which is pretty close, but not quite, and 6*6 is 36, so again, not quite. So, the square root of 44 is an irrational number; it's going to be a really long decimal. That means that what we have is actually a pretty good answer, but there are two mistakes that students tend to make without realizing that this is an okay answer. One of those mistakes is to divide the -4 by the -2 to get 2 +/- the square root of 44. This is not allowed because the + root 44 kind of gets in the way of you doing that division.
Another mistake is to divide the -4 and the 44 by the -2 to give us (-4/-2) +/- (square root of 44/-2). The problem with this is that dividing inside a square root like that isn't really allowed. That means that what we have here (x= -4 +/ - the square root of 44/-2) is actually the most mathematically correct answer. But since we're estimating, let's change it to a decimal by rounding the answers off. The square root of 44 is in between 6 and 7; it's actually about 6.633. That means we'll find our two answers by doing -4 + 6.633/-2 and also -4 - 6.633/-2. Doing that gives us our two estimated answers as -1.316 or 5.316. Our -1.316 answer is what would happen if the slingshot broke, so we're not too worried about that one. But over at 5.316 it looks like we're pretty close to our target but maybe a little short.
Maybe if we leveled out our shot a little bit our bird might fly a little further. Maybe like this? Okay, apparently now our equation is y = -3x^2 + 15x + 29, but again we want to know when the bird will hit the ground, or what the roots of the equation are. That means we substitute in y = 0 and begin thinking about which way we want to solve. We could try the factoring method here, but those numbers seem pretty messy, and there's also a good chance it won't work anyways, so let's go straight into the quadratic formula.
This means identifying a, b and c from our standard form quadratic. That makes a equal to -3, b equal to 15 and c equal to 29. Now it's just a matter of carefully substituting these values into the quadratic formula and then following the order of operations to come up with our two answers. Substituting the numbers in will look like this: x= -15 +/- (the square root of 15^2 - 4 (-3) (29)) /2 (-3).
Using a Negative B Value
Resulting example #2 problem after substituting values into formula
One other common mistake I see students make is to mess up the b value in the front left of the fraction. In the formula, it's a -b, so in this case 15 turns into -15. But often times your b value itself will be negative. When you have a -b and you plug it into the formula, - -b will turn it positive again, so you've got to be careful with that b in front.
Anyway, moving on to evaluating, we can start with the exponent on the inside - the b^2 part of the discriminant - and 15^2 gives us 225. Next, we do 4 * -3 * 29 to get -348, and we do 2 * -3 to get -6 on the bottom. Again, changing a minus negative into plus a positive will make our discriminant equal to 573. The square root of 573 is about 23.937. Doing -15 plus this and dividing by -6 will give us -1.489, and doing -15 minus this divided by -6 will give us 6.489.
We can again focus on the positive answer even though the negative one is a valid mathematical solution, and it looks like this one's going to work! I'm feeling pretty confident; let's let our furious fowl fly... and hey-o! We got it! You've now passed level two of Furious Fowls and are pretty good at solving quadratics, but are you ready for level three?
Lesson Summary
Let's quickly review what we learned from level two. Not every quadratic equation is factorable, so we need another way to solve them. Enter the quadratic formula. Using a, b and c from the standard form quadratic, we substitute these values into the formula and then use the order of operations to end up with our two answers.