if A and B are two numbers
A × B = HCF of A and B × LCM of A and B
AB = 12 & times; 168
also A-B = 60
Now we know that,
(A+B)2 - (A-B)2 = A2 + 2AB + B2 - (A2 - 2AB + B2 = 4AB
(A+B)2 = 4 × 12 × 168 + 602
(A+B)2 = 8064 + 3600 = 11664
or
since 11664 ends in 4, square will have 2 or 8 in end. so answer is 108 or 122
1202 = 120 × 120 = 144 × 100 = 14400
11664 < 14400
11664 < 1222
so answer is 108.
A + b = 108