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For arranging a picnic, each student contributed an amount equal to the number of students while the teacher contributed an amount equal to twice the number of students. However, if each student would have contributed an amount equal to twice the number of students and the teacher would have contributed an amount equal to the number of students, they would have generated Rs. 1056 more. Find the number of students in the group?
Let the number of students = x. Thus, we get,
[(2x2 + x) – (x2 + 2x)] = 1056
x2 - x - 1056 = 0
Solving the equation, we get, x = 33 or x = - 32.
Since the number of students are to be positive, number of students = x = 33
An amount of Rs.20,000 is to be distributed amongst P, Q, R and S such that “P” gets twice as that of “Q” and “S” gets four times as that of “R”. If “Q” and “R” are to receive equal amount, what is the difference between the amounts received by S and P?
We have, P = 2Q & S = 4R
Further Q = R & P + Q + R + S = 20,000
Thus we get, 2Q + Q + Q + 4Q = 20,000
8Q = 20,000 or Q = Rs. 2500
Thus, R = Rs. 2500, P = 5000 & S = Rs. 10000
Hence, the required difference = (S – P) = (10000 – 5000) = Rs. 5000
If 148 is multiplied first by 163 and then by 236, Which of the following numbers would come at the unit's place?
148 × 163 × 236 = 8 × 3 × 6 = 4 at the unit's place.
When the numbers are multiplied, the unit digit of the final product is obtained
as the product of the unit digits of individual numbers.
What will come in place of (a) in the following expression? a - 796.21 + 498.05 = 215.50 – 425.01
What will come in place of (a) in the following expression?
a - 796.21 + 498.05 = 215.50 – 425.01
a - 796.21 + 498.05 = 215.50 - 425.01
a = 88.65
What is the value of (12 + 22 + 32 + 42 + ----- + 102)
(12 + 22 + ….. + n2) = (1/6) n(n + 1) (2n + 1)
Here, n = 10
Therefore,
(12 + 22 + ….. + 102) = (1/6) 10 (10 + 1) ( 2 x 10 + 1)
= (1/6) x 10 x 11 x 21
= 385
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