Approach 1 — Direct Solving
Here milk : water = 7:5
That means quality of milk be 7 or
multiple 7
Only option A i.e. 21 is multiple of 7.
You can check by putting 21 as quantity of milk
Approach 2 — By solving
Water to Milk 5: 7
Let common factor be K, so water SK liters and Milk
Now, when we remove 9 liters mixture,
Now, 9 liter water is added,
So Water quantity SK-3.75+9 = 5K+5.25
Milk quantity 7K-5.25
K = 3
Amount of milk initially = 7k = 7 × 3 = 21