If x is an odd integer, is x x > x -x?
1) x 3 < x 2
2) xy ?
– y
The first thing you need to do when you get a question
this tough is to get the lay of the land, so to speak, by evaluating the
question stem.
This question is testing
Countinue
Negative exponents are not often tested on simpler problems because they're
considered more difficult math. However, they’re really straightforward:
they’re the reciprocal of the corresponding positive power. For example,
.
Now, this question is asking whether a number raised to itself is always
greater than that number raised the corresponding power of the opposite
sign. Think about the logic of the question: If x x > x -x
were always true or always false, regardless of the value of the number
involved, it wouldn’t make any sense to use this expression in a Data
Sufficiency question because the answer would just be a mathematical given
and you wouldn’t need any additional info. Just as it wouldn’t make any
sense for a Data Sufficiency question to ask "Is 5 > 4 ?"
So if the Exam asks "If x is an odd integer, isx x > x -x "
, there’s probably at least one exception to an otherwise consistent pattern.
The Exam is hoping you’ll see the general pattern and blank on the exceptions.
So far we have two number property characteristics determined for x:
we know it's odd and we know it's an integer, because the
stem tells us both. Our exception must deal with some other number property
characteristic.
Countinue
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