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Find the sum of all 2 digit numbers divisible by 3.
The number 243 has been divided into three parts in such a way that one third of the first part, fourth of the second part and half of the third part are equal. Determine the largest part.
It is given that 243 has been divided into 3 numbers x y and z for instance.
Second condition mentioned in the question is:
=> x/3 = y/4 =z/2
Clearly the biggest number is y. So let us solve w.r.t. y.
=> x = 3y/4
=> x =3z/2
=> z = y/2
=> x+y+z = 243
=> y/2 + 3y/4 + y = 243
9y/4 = 243
=> 243×4/9
=> 108
X divided by 899 gives a remainder 63. What remainder will be obtained by dividing X by 29?
What is the smallest number which is a perfect square and is divisible by 16, 20 and 24?
3600. The number is perfect square of 60.
It is divisible by 36 24 and 20. Only two numbers 3600 and 7200 fit these conditions.
It is clear that 3600 is the smaller number.
India has a run rate of 3.2 in the first 10 overs. What should be the run rate in remaining 40 overs to win a game of 282 runs?
Runs scored in first 10 overs:
=> Rate*Overs= 3.2*10 = 32 runs
=> Required runs = 282-32 = 250
=> Left overs= 40
Required rate = runs/overs
= 250/40
= 6.25
=> 6.25 runs per over is needed to win the game.
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