Lesson: Basic Arithmetic - 06t01
Apply Definitions To Questions, continued
[Page 6 of 24]
Solution to the question given in the previous section. Here, you were to use properties of numbers - negative and positive.
Video Lesson - Solving Inequalities
Click on the correct answer, then click Continue.
If x and y
are integers, xy > 0, and x + y < 0,
which of the following MUST be true? |
|
I. |
x and
y are both negative |
II. |
x
– y > 0
|
III. |
x
> y |
|
 |
None |
|
I only |
|
I and II only |
|
II and III only |
|
I, II and III |
|
Countinue
For starters, since xy > 0, x and y must
both be either positive or negative, and since x + y
< 0, x and y must both be negative.
Thus Statement I must be true, and answer choices (1) and (4)
can be eliminated.
Now try picking numbers:
If x = –3 and y = –2, then x
– y = (–3) – (–2) = –3 + 2 = –1
Thus Statement II doesn't hold, and Choices (3) and (5)
can be eliminated.
We've eliminated every answer choice except Choice (2) so it must be correct, and there's no need to go on to check Statement III.
In the next section you'll find other questionon the properties on numbers.
Next to display next topic in the chapter.
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