Positron emission occurs when an atom becomes more stable by
emitting a positron 01e, which is the same size
and mass as an electron but has a positive charge. This process
converts a proton into a neutron; the positron is emitted and the
neutron remains behind in the nucleus, decreasing the atomic number by
1.
Often the emission of an alpha or a beta particle creates another
radioactive species, which undergoes further radiation/emission in a
cascade called a radioactive series. Notice that in the course
of all of these types of radioactive decay, neither protons nor
neutrons are either created or destroyed: this is due to what’s known
as the law of conservation of matter, which states that mass is
neither created nor destroyed. So when you see radioactivity equations
on the SAT II Chemistry test, one of the most important things to
remember is that the sum of the mass numbers and the sum of the atomic
numbers must both be equal on both sides of the equation.
Example
Write the equation for the alpha decay of radium-221.Write the equation for the beta decay of sulfur-35.
Explanation
The radium-221 atom has atomic number (A) = 88 and mass number (Z) = 221. When an alpha particle is emitted, the atomic number is reduced by 2 and the mass number is reduced by 4. The atomic number of the resulting atom is 86, so the element created as a result of this radioactive decay is radon-217.
The sulfur-35 atom has an atomic number of 16 and a mass number of 35. When it undergoes beta decay, the atomic number is increased by 1 and the mass number remains the same. The atomic number of the atom created is 17, so the atom is chlorine-35.