Correct Answer: D
Explanation:
Algebra Sets and functions
Because it is given that 6 is the greatest number of individuals who can have birthdays in any particular month, these 66 people could be
evenly distributed across 11 of the 12 months of the year. That is to say, it could be possible for the distribution to be 11 X 6 = 66, and thus any given
month, such as January,would not have a person with a birthday. Assume that January has no people with birthdays, and see if this assumption
is disproved.
- (1) The information that more people have
February birthdays than March birthdays
indicates that the distribution is not even.
Therefore, March is underrepresented and
must thus have fewer than 6 birthdays. Since
no month can have more than 6 people with
birthdays, and every month but January already
has as many people with birthdays as it can have,
January has to have at least 1 person with a
birthday; SUFFICIENT.
- (2) Again, March is underrepresented with
only 5 birthdays, and none of the other months
can have more than 6 birthdays. Therefore, the
extra birthday (from March) must occur in
January; SUFFICIENT.
The correct answer is D; each statement alone is sufficient.